If it's not what You are looking for type in the equation solver your own equation and let us solve it.
22x^2+4x-658=0
a = 22; b = 4; c = -658;
Δ = b2-4ac
Δ = 42-4·22·(-658)
Δ = 57920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{57920}=\sqrt{64*905}=\sqrt{64}*\sqrt{905}=8\sqrt{905}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{905}}{2*22}=\frac{-4-8\sqrt{905}}{44} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{905}}{2*22}=\frac{-4+8\sqrt{905}}{44} $
| Y=|x+10| | | l-8=-1 | | 8-6b=-16 | | x-20+x-15+x-5+2x=360 | | 5v+9=-11 | | 3G-2h=-5 | | l-6=6 | | 18-4d/4=2-2d | | 1-5l=11 | | -15r=-33-5r | | 9+½=y+4 | | r/10=8 | | 10-3f=-5 | | 2+1x+5=3x-12 | | 9x^2-10x-3=0 | | 2x–6+2x-1=24 | | A(2y-5)=3(4y+7) | | 12-4r=-4 | | 17-(2x-1)⁴=1 | | (a-12)(a+2)-(a-3)(a-7)=45 | | 3x+2=3x–12 | | 100x-5=90 | | 2=6x+5 | | 8+3m=2 | | -1.4=7y | | 4+5k=29 | | 2^(2x+2)-2^(2x)=12 | | 0.00012=0.001x/2 | | -10z=-10 | | 8x-(3x-7)=8 | | x+3=3x+1x= | | 7x+11=-4 |